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chrispoole

Member

Registered: 2008-12-30

Posts: 121

Simple shell script, decrypt with gpg, pass to tar not work?

I wrote a simple shell function,

decrypt () {
    for i in "$@"; do
        if [ -d "$i" ]; then
            gpg -d "$i" | tar xzf - 
#            srm "$i"
        elif [ -f "$i" ]; then
            gpg -o ${i%.gpg} -d "$i"
            srm "$i"
        else
            echo "$i" is not a valid file or directory.
        fi
    done
}

I can pass it a list of files that I have encrypted with an encrypt() function: regular files just get gpg'd, and folders get tarred first.

Decrypting files works fine, but decrypting a folder does not. Why?

Addendum:

I can run the following line in an interactive shell:

gpg -d test\ directory.tgz.gpg | tar xzf -

This works fine. I get a directory called "test directory".

However, running

decrypt test\ directory.tgz.gpg

(which is the file that my encrypt() function produces) doesn't work, I just get a file "test directory.tgz", as though tar was never invoked.

I can't figure out why, but I'm sure it's something simple.

ber_t

Member

From: Berlin, Germany

Registered: 2010-03-10

Posts: 214

Website

Re: Simple shell script, decrypt with gpg, pass to tar not work?

Does changing

gpg -o ${i%.gpg} -d "$i"

to

gpg -o "${i%.gpg}" -d "$i"

have any effect?

chrispoole

Member

Registered: 2008-12-30

Posts: 121

Re: Simple shell script, decrypt with gpg, pass to tar not work?

Aha! I'm an idiot.

I wrote an encryption folder to check for whether the input is a file or folder, and tar any folder first.

Of course, the decryption folder will only ever be acting on files, some of which just happen to be directories originally.