[solved] Waiting for a process to exit in a bash script

manmachine · 2010-12-11 21:31:59

I'm trying to create a wrapper script for certain apps.
I need the script to keep running so I can execute commands before launching the application and after it exits. So I am not using 'exec' and I don't background the command that I want to run, and this works for most commands as intended.

However there is a specific application that causes the script to exit immediately, and keeps running as an orphan process.

I tried this in my script:

$command_to_run &
pid=$!
wait $pid

But it still doesn't work.
If I echo the $pid and check with ps later, I can see that the command is running with a *different* pid than the one reported in the script.
I suppose that the application exits early and launches itself in a different process?
Is there a way to workaround such behaviour?

Thanks

Last edited by manmachine (2010-12-13 11:22:25)

manmachine · 2010-12-13 11:22:08

Keeping things practical and simple is never a bad idea...turns out said application uses its own small binary launcher, by bypassing it and calling the main binary directly the script just works. Marking as solved.

Arch Linux

#1 2010-12-11 21:31:59

[solved] Waiting for a process to exit in a bash script

#2 2010-12-13 11:22:08

Re: [solved] Waiting for a process to exit in a bash script

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