[Solved] bash: Print both single and double quotes in a variable

Gen2ly · 2012-01-10 15:46:07

I have a variable that I'd like to assign that requires the string to be begin and end in both a single and double quote and I can't figure out how to do it. I think because of "variable expansion (is it?)" that bash is negating it. For example:

test='"string"'
echo $test
"string"

So obviously I try:

test=''"string"''
echo $test

Which is producing:

string

What I literally need the string to be is:

'"string"'

I haven't been able to find a way to do this. I know that this is unique. Does anyone know of a way to do this?

Last edited by Gen2ly (2012-01-10 18:30:30)

Trilby · 2012-01-10 15:55:21

test=\'\"string\"\'
echo $test
'"string"'

Trilby · 2012-01-10 16:01:55

Or if you want to risk going blind counting ticks

test="'"'"string"'"'"
echo $test
'"string"'

Gen2ly · 2012-01-10 18:04:52

ohh, should have figured. Thanks for the help Trilby.

Arch Linux

#1 2012-01-10 15:46:07

[Solved] bash: Print both single and double quotes in a variable

#2 2012-01-10 15:55:21

Re: [Solved] bash: Print both single and double quotes in a variable

#3 2012-01-10 16:01:55

Re: [Solved] bash: Print both single and double quotes in a variable

#4 2012-01-10 18:04:52

Re: [Solved] bash: Print both single and double quotes in a variable

Board footer