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alphaniner

Member

From: Ancapistan

Registered: 2010-07-12

Posts: 2,810

[SOLVED]mdadm --replace --with on healthy RAID 0

I have four disks with two partitions, each set of partitions part of a different four-device RAID (0 & 10). Both arrays are healthy, but I'd like to replace one of the disks (swap SATA 3 with SATA 2). I figure I'll stop the RAID 0 until the swap on the 10 is complete to avoid any complications. But does anyone know if the "--replace X --with Y" method works for a RAID 0? It's just throw-away data, so I'll probably try it unless someone knows it doesn't work. Thanks.

Last edited by alphaniner (2016-01-23 22:15:21)

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But whether the Constitution really be one thing, or another, this much is certain - that it has either authorized such a government as we have had, or has been powerless to prevent it. In either case, it is unfit to exist.
-Lysander Spooner

alphaniner

Member

From: Ancapistan

Registered: 2010-07-12

Posts: 2,810

Re: [SOLVED]mdadm --replace --with on healthy RAID 0

Finally got around to doing this. Not surprisingly, mdadm doesn't allow adding a spare to a RAID 0. So much for the UNIX philosophy and not preventing "stupid... clever things".

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But whether the Constitution really be one thing, or another, this much is certain - that it has either authorized such a government as we have had, or has been powerless to prevent it. In either case, it is unfit to exist.
-Lysander Spooner