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Script: exploit.delivery/systemd_journald_exploit_no_aslr.py
To start it, you need to disable ASLR and therefore I launch it like this: setarch `uname -m` -R ./systemd_journald_exploit_no_aslr.py
It takes 2 seconds and the script goes with code 0, I don’t get root access to the system. What to do????
Last edited by Copied (2019-02-08 05:59:29)
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There are a couple constants in there that define the location of libc and the stack that claim they need to be set on a per system basis. Have you tried to set them for your system?
This won't work with ASLR; why is it you think that command you presented will turn off ASLR? It seems to be that would have to be a boot option.
You call this an 'Audit'. Is the point of this to check as to whether this exploit exists? Or this or this?
Edit: I liked this quote from the author:
"We are also considering providing a full ASLR bypass, but are weighing whether we are lowering the bar too much for the kiddies," Gregory added.
Last edited by ewaller (2019-02-08 16:07:58)
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