Arch Linux

Fauveboy

Member

Registered: 2019-08-03

Posts: 33

Python3.8.0 asyncio.async syntax error

- I've installed Python3.8.0
- run this script: http://ix.io/24pV
- and get this error: http://ix.io/24pU

is this function simply missing from the latest python version? how can I correct that?

loqs

Member

Registered: 2014-03-06

Posts: 17,328

Re: Python3.8.0 asyncio.async syntax error

Something like the following?

        if hasattr(asyncio, 'ensure_future'):
           ensure_future = asyncio.ensure_future
        else:  # use of async keyword has been Deprecated since Python 3.4.4
           ensure_future = asyncio.async
        self.faders = [ensure_future(self.fade_to(f, 0)) for f in range(self.grid.width)]

Fauveboy

Member

Registered: 2019-08-03

Posts: 33

Re: Python3.8.0 asyncio.async syntax error

so I changed inserted your suggested code here: http://ix.io/24ui
but it leads to this error: http://ix.io/24uj

what is your suggestion meant to solve? I guess for the conditions to happen it still needs to no what .async is ? Is .ensure_future supposed to be an alternative to .async?

loqs

Member

Registered: 2014-03-06

Posts: 17,328

Re: Python3.8.0 asyncio.async syntax error

What about this instead?

        if hasattr(asyncio, 'ensure_future'):
           ensure_future = asyncio.ensure_future
        else:  # use of async keyword has been Deprecated since Python 3.4.4
           ensure_future = getattr(asyncio,'async')
        self.faders = [ensure_future(self.fade_to(f, 0)) for f in range(self.grid.width)]