Remove with dependencies

calexico · 2004-02-11 12:55:06

Well I'm not sure if this topic as already be solved but here is a little bash function I wrote to do it :

myremove() {
        # save package list
        lspac > tmp1

        # remove packages
        rmpac $*

        # new list for comparison
        lspac > tmp2

        # packages to remove during next step
        NEWLISTE=`diff tmp1 tmp2 | grep > | cut -d " " -f2 | tr "n" " "`

        if [ -n "$NEWLISTE" ]; then
                # remove dependencies
                myremove $NEWLISTE
        else
                # remove tmp files
                rm tmp1 tmp2
        fi
}

with :

alias lspac="pacman -Qi --orphan | cut -d ' ' -f1"
alias rmpac="pacman -Rn"

Well it works and that's all, no confirmation etc but I think it should be easy to implement. The basic idea behind this is that if you remove a package and that package has a dependency, let say X, you have two choice :
- either something else uses X and you won't remove it because it won't appear in the list of "orphan packages"
- either nothing uses it and it appears in the orphan list, so it will be removed during next call

Hope it will be helpfull.

sarah31 · 2004-02-11 12:58:01

i thought that is what the cascading removal option was?

calexico · 2004-02-11 13:03:05

Well in fact I think that the cascade package remove packages depending on the one you're removing to avoid breaking dependencies, whereas what I do is removing the unused dependencies.

if you've got : X -> Y -> Z

and you remove Y

- pacman -Rc removes X and Y
- I remove Y and Z if Z is unused

(hoping I'm right ant the cascade option does this)

calexico · 2004-03-02 19:06:10

Well this is now obsolete since the "--recursive" option has been added (see pacman changelog)

Good news

Arch Linux

#1 2004-02-11 12:55:06

Remove with dependencies

#2 2004-02-11 12:58:01

Re: Remove with dependencies

#3 2004-02-11 13:03:05

Re: Remove with dependencies

#4 2004-03-02 19:06:10

Re: Remove with dependencies

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