Python and xslt

vredfreak · 2006-12-19 18:05:56

Ok, I'm an infant in Python and I've got a problem that is driving me nuts.

I download a xml page(with terrible formatting), then use xslt to format the page into a workable form, and save the result to a new file. But when I try to read the new file so that I can parse it, I get "Permission denied" messages. I have something like this:

def formatPage():
    styledoc = libxml2.parseFile(whatever.xslt)
    style = libxslt.parseStylesheetDoc(styledoc)
    doc = libxml2.parseFile(foo)
    result = style.applyStylesheet(doc, None)
    style.saveResultToFilename(foo_bar, result, 0)
    style.freeStylesheet()
    doc.freeDoc()
    result.freeDoc()

def parsePage():
    temp_file = os.popen(foo_bar)
    file = temp_file.read()

I'm assuming that "foo_bar" is still open by xslt and that's why I can't read the file. But for the life of me, I can't figure out how to relinquish control of the file.

Thanks for any help.

arooaroo · 2006-12-19 20:11:45

I may be misinterpreting your intentions, but to os.popen is for running external commands (opens a pipe) and doesn't return a file object.

To read a file:

foobar = 'a_file.txt'
temp_file = open(foo_bar)
filecontents = temp_file.read()

twiistedkaos · 2006-12-19 21:07:02

Yes, I would do it the same was as aroo is mentioning

vredfreak · 2006-12-19 23:22:39

arooaroo wrote:

I may be misinterpreting your intentions, but to os.popen is for running external commands (opens a pipe) and doesn't return a file object.
To read a file:
foobar = 'a_file.txt'
temp_file = open(foo_bar)
filecontents = temp_file.read()

Doh! Now I feel silly. :oops: Originally I was reading straight from stdout and forgot to fix that when I realized I would have to read from a file.

Thanks arooaroo and twiistedkaos.

Arch Linux

#1 2006-12-19 18:05:56

Python and xslt

#2 2006-12-19 20:11:45

Re: Python and xslt

#3 2006-12-19 21:07:02

Re: Python and xslt

#4 2006-12-19 23:22:39

Re: Python and xslt

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