question about port C++ code to C

gobeav3rs297 · 2010-04-23 23:56:28

I have a newbie question about C++

I'm being ask to port a C++ sharelib into a kernel driver for work so from C++ => C. I'm not at all familiar with C++ but i'm making some leeway. However i'm a little stuck, what does the following line of code in bold mean in C++ and how would I translate it into C code?

#include <deque>

...
...
...

struct _buffer
{
UINT8* buffer;
UINT8 length;
};

typedef deque< struct _buffer* > MSGQUEUE;

I'm assuming it's type defining a deque of the struct _buffer??? but I'm confused by the <...>, what does that operator do in C++. Is it defining a struct _buffer pointer within the deque???

This might like a "DUH it means...." question to some people so sorry about the stupid question.

--Vincent

Allan · 2010-04-23 23:59:30

<> is template syntax and is generally the type of object a container holds.. So it is defining that the MSGQUEUE type is a deque holding struct_buffer*'s.

gobeav3rs297 · 2010-04-24 00:33:40

thank you very much for the explaination

--Vincent

Arch Linux

#1 2010-04-23 23:56:28

question about port C++ code to C

#2 2010-04-23 23:59:30

Re: question about port C++ code to C

#3 2010-04-24 00:33:40

Re: question about port C++ code to C

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