awk - insert an external variable [solved]

graysky · 2011-11-27 14:57:00

I want to incorporate the variable in the for statement as a column of my processed file. In the INCORRECT example below, it is $i which corresponds to the i in my for loop:

for i in x86_64 i686; do
  awk '{ print $1" "$4" "$5" "$i }' $file-$i > processed-$i.log
done

Thanks!

EDIT: finally found the solution (choice of key words is critical to success) in this old thread.

for i in x86_64 i686; do
  awk -v arch=$i '{ print $1" "$4" "$5" "arch } ' $file-$i > processed-$i.log
done

Last edited by graysky (2011-11-27 15:11:08)

karol · 2011-11-27 15:21:13

I don't get your use of quotes. Wouldn't

awk -v arch=$i '{ print $1 $4 $5 arch }'

work?
"$5" prints a literal "$5" here instead of what's in the 5th column.

Last edited by karol (2011-11-27 15:22:36)

falconindy · 2011-11-27 15:26:26

The quotes are between the vars, not around them... better to use commas to separate:

awk -v arch=$i  '{ print $1, $4, $5, arch }'

Last edited by falconindy (2011-11-27 15:26:50)

keenerd · 2011-11-27 15:28:46

What are you doing in a larger context? I can't tell what is going on here, but if you are working with a list of packages then Expac would be better suited.

karol · 2011-11-27 15:30:23

falconindy wrote:

The quotes are between the vars, not around them... better to use commas to separate:
awk -v arch=$i  '{ print $1, $4, $5, arch }'

A great lesson in perspective and code readability.
Thanks!

graysky · 2011-11-27 16:35:10

@falconindy - I thought of that but I wanted to use spaces for this application. As you pointed out, the quotes are not to protect the vars, but to add the space between them.

@keenerd - just analyzing my unofficial repo log files to generate some statistics for users. BTW, expac looks pretty slick!

falconindy · 2011-11-27 16:53:32

graysky wrote:

@falconindy - I thought of that but I wanted to use spaces for this application.

...and unless you mess with the OFS, that's exactly what it does.

Arch Linux

#1 2011-11-27 14:57:00

awk - insert an external variable [solved]

#2 2011-11-27 15:21:13

Re: awk - insert an external variable [solved]

#3 2011-11-27 15:26:26

Re: awk - insert an external variable [solved]

#4 2011-11-27 15:28:46

Re: awk - insert an external variable [solved]

#5 2011-11-27 15:30:23

Re: awk - insert an external variable [solved]

#6 2011-11-27 16:35:10

Re: awk - insert an external variable [solved]

#7 2011-11-27 16:53:32

Re: awk - insert an external variable [solved]

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