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Anyone able to help me with this -lirn arg.
-n should give me the line number, but it isnt? I am using ZSH, but i tried with regular bash but it gives me same output?
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It appears to be a pretty simple reason: the "-l" command will cause grep to print only the filename of a file that matches. It appears to have a higher priority than th "-n" command.
...also, using both "-l" and "-n" doesn't make much sense to me. "-l" says to only print the filename and print it only once, even if there are multiple matches in a file. If the phrase you're looking for is in the file three times, how would grep even display the matching line numbers?
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I'm guessing you maybe copied this from somewhere and are wondering why it isn't working the same way... in which case, are you sure it's supposed to be -l (lowercase L) and not -I (uppercase i)? -I makes sense with -r because it causes grep to skip files that look like they contain binary data.
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#3 hmm i didnt copied it from anywhere.. But you gave me the correct answer.. thank you
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