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ThunderRush

Member

From: Austria

Registered: 2013-01-31

Posts: 22

Bash Script with a Syntax Error

I have a short question, and I'm breaking my - my probably stupid - head over it.

#!/bin/bash

if [ "$1" = "-p" ]
then
        echo -e "Doing a Pacman-Update with \e[0;31mStandard\e[00m settings."
        pacman -Suyy
elif [ "$1" = "-y" ]
        if [ "$2" = "-s" ]
        then
                echo -e "Doing a Yaourt-Update \e[0;31mwithout asking\e[00m!"
                yaourt -Suyy --aur --noconfirm
        else
                echo -e "Doing a Yaourt-Update \e[0;31mwith asking\e[00m!"
                yaourt -Suyy --aur
        fi
#else
#       echo -e "Please specify the correct options! packages [-p] [-y] [-s]"
fi

Returns...

/scripts/packages: Zeile 18: Syntaxfehler beim unerwarteten Wort (Syntaxerror at unexpected word) `fi'
/scripts/packages: Zeile 18: `fi

Why is fi and unexpected word? It closes my first if. Does not work with the else either, then it says that else is unexpected.
I hope bash does not expect a bush of flowers and a goldring from me.

Last edited by ThunderRush (2013-01-31 13:26:18)

portix

Member

Registered: 2009-01-13

Posts: 757

Re: Bash Script with a Syntax Error

bash expects a then after elif.

---

dwb

gridcol

Guest

Re: Bash Script with a Syntax Error

Try to put a second "then" after your line with the elif. Should work fine then.

Last edited by gridcol (2013-01-31 13:30:00)

ThunderRush

Member

From: Austria

Registered: 2013-01-31

Posts: 22

Re: Bash Script with a Syntax Error

Thank you two guys a lot. I asked someone who was supposed to know such stuff, but he said that I don't need a than after elif.
Thanks again.