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The PKGBUILD Wiki page states that
The BSD, MIT, zlib/png and Python licenses are special cases and could not be included in the licenses package.
Can someone explain why this is? I rather like both the BSD and MIT licenses.
Last edited by pgoetz (2014-03-31 20:38:00)
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Maybe you should read the entire section!
The BSD, MIT, zlib/png and Python licenses are special cases and could not be included in the licenses package. For the sake of the license array, it is treated as a common license (license=('BSD'), license=('MIT'), license=('ZLIB') and license=('Python')) but technically each one is a custom license because each one has its own copyright line. Any packages licensed under these four should have its own unique license stored in /usr/share/licenses/pkgname. Some packages may not be covered by a single license. In these cases, multiple entries may be made in the license array, e.g. license=('GPL' 'custom:name of license').
"but technically each one is a custom license because each one has its own copyright line."
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Thanks. I did read that; am not sure why it didn't register in my brain. I think It's because I only just now realized what is meant by "each one has its own copyright line".
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I rather like both the BSD and MIT licenses.
If a license is not included in the license package, it does not mean you can't use that license. ;-)
we are not condemned to write ugly code
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Closing this old thread.
Nothing is too wonderful to be true, if it be consistent with the laws of nature -- Michael Faraday
Sometimes it is the people no one can imagine anything of who do the things no one can imagine. -- Alan Turing
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