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I am completely new to arch Linux and tried finding solution to this simple solution but didn't get any solution.
I have grub installed in separate drive mounted as /boot and i want the grub to boot windows by default. kindly help me with this.
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I don't know what you searched for but...
https://wiki.archlinux.org/index.php/GR … menu_entry
Don't forget to rerun grub-mkconfig to the correct destination after making the change
Last edited by V1del (2017-08-04 12:30:15)
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See I m a complete noob here.
How am I supposed to get the number which I have to use with GRUB_DEFAULT=0?
In grub, while switching on the system, windows is at the 3rd position so I changed GRUB_DEFAULT=3 in /etc/default/grub and ran grub-mkconfig but nothing changed.
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How did you install Arch? What other operating systems do you have on the machine (what are in positions 1 and 2 in your boot order)?
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Grub identifies entries in generated menu counted from zero. That means 0 for the first entry which is the default value, 1 for the second and so on.
How did you install Arch? What's the output of
uname -a?
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I used to use Ubuntu previously but things work differently here. I have Windows 10 and arch linux installed(trying first time). The second option in grub will be failesafe(may be)
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