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Hi there,
I recently noticed that neovim-git is out-of-date. It has been flagged as such and I was wondering what would be the steps to adopt it?
Indeed, when reading the AUR submission guidelines, it says:
If it is unmaintained or the maintainer is unresponsive, the package can be adopted and updated as required.
But I haven't found more precision on how to do that.
Could anyone point me in the right direction?
I am sorry if it's explained somewhere and I missed it...
Thanks in advance!
Last edited by nedsi (2022-09-12 13:27:01)
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Great thanks! I previously found the page it redirects to, but not the one you linked.
Thanks again!
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How can a -git-package be out ouf date?
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How can a -git-package be out ouf date?
If it needs maintainer action (eg. build system changed, new deps, sources are wrong,...)
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For moving or disappearing of the sources the ood flag might be somewhat relevant, the other things mentioned are build failures.
The out of date flag is NOT meant for a build failure.
I am - and have been for years - maintaining aur vcs packages.
If someone flags one of my vcs packages as ood because of a build failure I reset the ood flag and add a comment the package is currently broken.
If the user had posted that comment the maintainer doesn't have to and also everyone following/seeing the comments would be aware of the issue.
Last edited by Lone_Wolf (2022-09-13 10:25:18)
Disliking systemd intensely, but not satisfied with alternatives so focusing on taming systemd.
(A works at time B) && (time C > time B ) ≠ (A works at time C)
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If you try to flag a VCS package in the AUR, it is clearly stated when the flagging should be done, which is what I wrote (more or less).
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I checked and it looks like the text was changed recently and does mention upstream changes as a valid reason for flagging VCS packages ood.
Whether I'll change my response to ood flag wil depend largely on the amount of false positives .
Disliking systemd intensely, but not satisfied with alternatives so focusing on taming systemd.
(A works at time B) && (time C > time B ) ≠ (A works at time C)
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