[SOLVED] Script to extract all 7z files in a dir named after each file

rado84 · 2024-02-03 20:31:39

I modified one of my scripts (originally it converts mka to ac3) to extract all 7z files in a directory with the same name as each 7z archive but for some reason it doesn't work.

This is the script after my modification:

#!/usr/bin/env bash

for name in *.7z; 
do 
    newname=$(echo "$name" | rev | cut -f 2- -d '.' | rev)
    7z x "$name" "$newname/" -mmt=8;
done

When executed, it shows some info in terminal and ends pretty quickly without creating the directories which in my POV means it doesn't work. This is what the terminal displays:

Extracting archive: Writing The Future.7z
--
Path = Writing The Future.7z
Type = 7z
Physical Size = 12371317
Headers Size = 192
Method = LZMA2:12m
Solid = +
Blocks = 1


No files to process
Everything is Ok

Files: 0
Size:       0

What am I missing here?

Last edited by rado84 (2024-02-04 08:09:47)

rado84 · 2024-02-04 08:09:33

I made it work:

7z e -y "$name" -o"$newname/"

You can delete the topic.

ayekat · 2024-02-04 09:53:26

rad84 wrote:

You can delete the topic.

We don't do that here.
https://wiki.archlinux.org/title/Genera … way_street

Arch Linux

#1 2024-02-03 20:31:39

[SOLVED] Script to extract all 7z files in a dir named after each file

#2 2024-02-04 08:09:33

Re: [SOLVED] Script to extract all 7z files in a dir named after each file

#3 2024-02-04 09:53:26

Re: [SOLVED] Script to extract all 7z files in a dir named after each file

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