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#1 2025-12-14 04:53:39
- SubGothius
- Member
- Registered: 2009-04-07
- Posts: 15
makepkg.conf new NPROC option
Noticed pacman just gave me a /etc/makepkg.conf.pacnew containing a new option NPROC=2
According to makepkg.conf(5):
NPROC=""
Sets the number of processors to use for parallel jobs in makepkg. Note: this does not affect parallelization of tasks during ``build()`` and related functions.
Reckon I could set that to NPROC="$(nproc)" (or should that be NPROC=$(nproc) ?) to have it simply use the number of processors available, yeah?
Best regards,
-Tye
"In theory, there's no difference between theory and practice, but in practice, there is." (-Jan L.A. van de Snepscheut)
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#2 2025-12-14 05:38:52
- Allan
- Pacman
- From: Brisbane, AU
- Registered: 2007-06-09
- Posts: 11,619
- Website
Re: makepkg.conf new NPROC option
Reckon I could set that to NPROC="$(nproc)" (or should that be NPROC=$(nproc) ?) to have it simply use the number of processors available, yeah?
Yes - it currently only speeds up stripping of debug symbols at the moment.
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#3 2025-12-14 05:56:27
- SubGothius
- Member
- Registered: 2009-04-07
- Posts: 15
Re: makepkg.conf new NPROC option
Cool, thx! So, should that $(nproc) be quoted here or nah?
Best regards,
-Tye
"In theory, there's no difference between theory and practice, but in practice, there is." (-Jan L.A. van de Snepscheut)
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#4 2025-12-14 06:47:38
- Allan
- Pacman
- From: Brisbane, AU
- Registered: 2007-06-09
- Posts: 11,619
- Website
Re: makepkg.conf new NPROC option
Cool, thx! So, should that $(nproc) be quoted here or nah?
No quote. (it actually makes no difference...)
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