My first shot at ZSH

Vintendo · 2009-03-23 14:09:16

I am trying to rewrite the preexec method in zsh but I am having some difficulties. This is what I've got so far:

preexec () {
    $command = $1
    if [$command == "ssh 192.168.0.100"]; then
        $command = "Server"
    fi
    print -Pn "\ek$command\e\\"
}

But it doesn't work. It says:

preexec:1: command not found: =
preexec:2: = not found

andre.ramaciotti · 2009-03-23 14:52:51

What do you want to do? If $command is equal to that string, replace its value with "Server"?

You should be doing:
command="Server"
then (without spaces around the = and with no $ at the beginning)

Vintendo · 2009-03-23 15:04:07

What I want to do is change the screen title to the command that's running. But if it's ssh * I want it to be server. The print -Pn statement changes the title.

I now have:

preexec () {
    $command = $1
    if [$command == "ssh 192.168.0.100"]; then
        command="Server"
    fi
    print -Pn "\ek$command\e\\"
}

But that doesnt work as wel.

andre.ramaciotti · 2009-03-23 15:14:41

preexec () {
    command=$1
    if [[ $command == "ssh 192.168.0.100" ]]; then
        command="Server"
    fi
    print -Pn "\ek$command\e\\"
}

I guess it should work now. When you're setting a parameter value, you shouldn't use the dollar sign nor put spaces around the equal sign. And preferably, use [[ and ]] when using the if statement with zsh.

edit: typo

Last edited by andre.ramaciotti (2009-03-23 15:19:48)

Vintendo · 2009-03-23 15:22:05

Thanks. It works like a charm now

Arch Linux

#1 2009-03-23 14:09:16

My first shot at ZSH

#2 2009-03-23 14:52:51

Re: My first shot at ZSH

#3 2009-03-23 15:04:07

Re: My first shot at ZSH

#4 2009-03-23 15:14:41

Re: My first shot at ZSH

#5 2009-03-23 15:22:05

Re: My first shot at ZSH

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