simple cmd line help

loudtiger · 2009-04-28 16:16:37

not sure this is the forum to post this in, but here goes:

say i wanted to chown a bunch of files with a criteria. how would i do that?

i was thinking to chown today's modified files, for example, i would do something like

ls -la | grep "2009-04-28" > chown me

or something to that effect. obviously that's not the right line though. can someone get me pointed in the right direction? or a better way?

thanks for all of your help

Procyon · 2009-04-28 16:28:43

man find

It can both check for modification time with -mtime and run a command on the found file with -exec

brisbin33 · 2009-04-28 17:45:49

comon Procyon, that's no fun!

ls -la | grep "2009-04-28" | awk '{print $8}' | while read file; do chown me $file; done

just kidding, find is definitely the way to go

loudtiger · 2009-04-29 14:54:16

sweet, this is perfect. thanks guys

klixon · 2009-04-29 15:55:57

brisbin33 wrote:

comon Procyon, that's no fun!
ls -la | grep "2009-04-28" | awk '{print $8}' | while read file; do chown me $file; done
just kidding, find is definitely the way to go

pftt... loose the grep... it will save you milliseconds!

ls -la | awk '/2009-04-28/ {print $8}' | while read file; do chown me $file; done

brisbin33 · 2009-04-29 16:46:54

@klixon

haha indeed! plus you could be more targeted

ls -la | awk '{if ($6 == "2009-04-28") print $8}' | while read file; do chown me $file; done

oneupsmanship ftw!

Arch Linux

#1 2009-04-28 16:16:37

simple cmd line help

#2 2009-04-28 16:28:43

Re: simple cmd line help

#3 2009-04-28 17:45:49

Re: simple cmd line help

#4 2009-04-29 14:54:16

Re: simple cmd line help

#5 2009-04-29 15:55:57

Re: simple cmd line help

#6 2009-04-29 16:46:54

Re: simple cmd line help

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