can't get a variable to execute in my bash script [SOLVED]

graysky · 2010-03-03 22:51:41

I am trying to figure out why I can't get a variable ($switches in the script below) to output correctly in my bash script but am at a loss to do so. Calling the variable within the for loop results in a null value for it even though I have defined it. The variable just needs to replace the -V 2 text in the commented line right above it. It simply does not work.

How can I force my encode routine to read the vars in without redefining them within it?

#!/bin/bash

cores=4
switches="-V 2"

encode() {
for file; do
fileout=$(echo "$file" | sed s'/.wav//')
#lame -V 2 "$file" "$fileout".mp3; done
lame "$switches" "$file" "$fileout".mp3; done
}

export -f encode
find . -name '*.wav' -print0 | xargs -0 -n 1 -P $cores bash -c 'encode "$@"' --

Last edited by graysky (2010-03-03 23:29:33)

raf_kig · 2010-03-03 23:05:47

your encode part is running in a subshell, try export switches="-V 2"

graysky · 2010-03-03 23:28:51

OK! I got it now, thanks! The variables are defined in /etc/multilame.conf

#!/bin/bash

. /etc/multilame.conf

encode() {
. /etc/multilame.conf
for file; do
fileout=$(echo "$file" | sed s'/.wav//')
lame "$switches" "$file" "$fileout".mp3; done
}

export -f encode
find . -name '*.wav' -print0 | xargs -0 -n 1 -P $cores bash -c 'encode "$@"' --

Last edited by graysky (2010-03-03 23:29:15)

Arch Linux

#1 2010-03-03 22:51:41

can't get a variable to execute in my bash script [SOLVED]

#2 2010-03-03 23:05:47

Re: can't get a variable to execute in my bash script [SOLVED]

#3 2010-03-03 23:28:51

Re: can't get a variable to execute in my bash script [SOLVED]

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